THERMODYNAMICS

Answer :

[(Δc) / (100°)] = [(ΔF) / (180°)]

                   given : Δc = 25°C

                   ∴ [(25) / (100)] = [(ΔF) / (180°)]

                   ∴ Δ F = [(180) / 4] = 45°F

Answer :

Absolute zero on celcius scale = – 273.15° C

Answer :

Temperature increases by 27°C. on Kelvin scale increment will be same.

                   Hence value of increase is 27K   

Answer :

Density of water is maximum at 4°C

                             (C/5) = [(F – 32) / 9]

                   ∴       (4/5) = [(F – 32) / 9]

                   ∴       F = 39.2° F 

Answer :

Slope of BC = [(Y₂ – Y₁) / (X₂ – X₁)]        

                                      = [(100 – 0) / (212 – 32)]

                                      = [(100) / (180)] = (5/9)

                   i.e slope of AB = slope of BC = (5/9)