Time%20Work

1 )

Sheetal is twice as good as workman as Babita and together they finish a piece of work in 18 days. Find the total number of days in which Babita can finish the work.

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Answer :

As per question, Sheetal does twice the work as done by Babita.

So A:B = 2:1.

Also (Sheetal+Babita) one day work is 1/18
To get days in which Babita will finish the work, lets calculate work done by Babita in 1 day =(118 ∗13 )=154.

So Babita will complete the work in 54 days

2 )

Riya can complete a piece of work in 5 days, but with the help of her son she can do it in 3 days. Find the time taken by the son alone to complete the work.

7.5 days

7 days

8.5 days

8 days

9 days

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Answer :

In this type of question, where we have one person work and together work done.

Then we can easily get the other person work just by subtracting them.

As, Son's one day work = (1/3 −1/5 ) = (5−3/15 ) = 2/15
So son will do whole work in 2/15 days = 7.5 days

3 )

Two pipes can fill the cistern in 10 hr and 12 hr respectively, while the third pipe can empty it in 20 hour simultaneously, if all the pipes are opened then the cistern will be filled in

6.5 hr

7.5 hr

9 hr

10 hr

8.5 hr

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Answer :

Work done by all the tanks working together in 1 hour. ⇒ 1/10+1/12-1/20=2/15.

Hence, tank will be filled in 15/2= 7.5 hour.

4 )

A is 30% more efficient than B. How much time will they, working together, take to complete a job which A alone could have done in 23 days?

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Answer :

Ratio of times taken by A and B = 100: 130 = 10: 13,
Suppose B takes x days to do the work.
Then, 10: 13:: 23 : x => x = ( 23*13 / 10 ) -> x = 299 / 10

A's one day work 1/23

B's one day work 10/299
A and B together can complete the job in 13 days.

5 )

A does half as much work as B in three-fourth of the time. If together they take 18 days to complete the work, how much time shall B take to do it?

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Answer :

Suppose B takes x days to do the work
A takes ( 2 * 3/4 x) = 3x/2 days to do it
(A+B)’s 1 day’s work = 1/18

1/x + 2/3x = 1/18 or

x = 30

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