Mixtures

Answer :

Suppose the Container initially contains 8 liters of liquid.

Let x liters of this liquid be replaced with water.

Water in new mixture = (3-3x/8+x)

Milk in new mixture = (5-5x/8)

Then (3-3x/8+x) = (5-5x/8)

5x + 24 = 40 - 5x

10x = 16==>x=8/5

So part of mixture replaced is 8/5*1/8=1/5

Answer :

Ratio of only milk in Can A = 4 : 5

Ratio of only milk in Container B = 3 : 5

Let ‘x’ be the quantity of milk in Container C

4/5......................... 3/5

................ x

3/5-x.................... x - 4/5

(3/5-x)/(x-4/5) =1/1

X=7/10

Therefore, quantity of milk in Container C = 7

=> Honey quantity = 10 - 7 = 3

Hence the ratio of milk & honey in Container 3

is 7 : 3

Answer :

If quantity of cold drink as x and alcohol as x+3.

(x+3)/x=3/2

Cold drink x=6 and alcohol = x+3 = 9 liters

Answer :

127............................... 132

..................... 130

2................................... 3

Then

129.................... 132

................ 130

1........................... 2

Hence final ratio is 2 : 2: 3+1 ==>1:1:2

Answer :

Let CP of 1 liter milk be Rs 1

Then SP of 1 liter of mixture = Rs 1 Gain

25%

CP of 1 liter mixture =Rs (100/125*1) = 4/5

Milk……………….Water

1……………………0

…………..4.5

4.5………………….1.5

Ratio 4:1

Hence percentage of water in mixture

= (1/5*100) = 20%