Bar Graph

Answer :

Step 1:
Total population of State A = 410 Lakhs
Step 2:
Average Population of State A = Total population of State A / Number of Years
Step 3:
By substituting the values in the formula,
410/ 7 = 58.7
Therefore, The approx average population of State A is 58%

Answer :

Step 1:
As we need to find ratio,
State A (2001 + 2002 + 2003) : State B(2005 + 2006 +2007)
Step 2:
By substituting the values in the above formula,
(40 + 45 + 60) : (80+ 90+100) (Substituting the values in the formulas)
Step 3:
By simplification,
= 145 : 270
= 29:54
Therefore the ratio of number of people in the state A( 2001 + 2002 + 2003)to the number of people in the state B( 2005 + 2006+ 2007) is 29 : 54

Answer :

Step 1:
As we need to find the percentage rise in the population, we use
Percentage Increase = [(final - Initial) /Initial] x 100
=Difference /Initial x 100

Percentage Increase = (Population of state B during 2004 - 2003/ 2003) x 100
Step 2:
By substituting the values in the formulas, = [(70 - 60)/60 x 100]
=10/60 x 100
= 1/6 x 100
= 16.66%
Therefore, there has been a rise in 16.66% of population during the year 2003 and 2004 in State B.

Answer :

Step 1: As we need to find the total difference in the population of State A and State B, we can individually take the difference for each year and add all the differences to find the difference between total population of State A and State B.
Total A - Total B = Difference(First year) , Difference(Second year) Difference(Third year) , Difference( Fourth year) , Difference(Fifth year) , Difference(Sixth year) , Difference(Seventh year).
Step 2:
By substituting the values in the above formula,
(-10)+5+0+(-20)+(-10)+(-25)+(-20)
= -80 Lakhs
Therefore, The difference in their population is 80 lakhs.

Answer :

State B - 2003:

Percent rise = Difference / Initial x 100

= (60 - 40)/40 x 100

= 20/40 x 100

= 50%

By using the formula,

find out the percentage rise in population for both states respective to all the years and select the correct option.